sederhanakan bentuk akar berikut? √196= √18= plisssssssssssss tolong dong di jawab
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Penjelasan dengan langkah-langkah:
Nomor 1)
[tex] = \sqrt{196} [/tex]
[tex] = \sqrt{14 \times 14} [/tex]
[tex] = \sqrt{ {14}^{2} } [/tex]
[tex] = {14}^{ \frac{2}{2} } [/tex]
[tex] = {14}^{1} [/tex]
[tex] = 14[/tex]
Nomor 2)
[tex] = \sqrt{18} [/tex]
[tex] = \sqrt{9 \times 2} [/tex]
[tex] = \sqrt{ {3}^{ \cancel{2}} \times 2 } [/tex]
[tex] = 3 \sqrt{2} [/tex]
[answer.2.content]
